Proving the Trigonometric Identity: cos^4x - sin^4x cos^2x - sin^2x
Proving the Trigonometric Identity: cos4x - sin4x cos2x - sin2x
To prove the trigonometric identity (cos^4 x - sin^4 x cos^2 x - sin^2 x), we can utilize the difference of squares formula. Let's go through this step by step.
Step 1: Factoring Using the Difference of Squares Formula
The difference of squares identity is given by:
[text{a}^2 - text{b}^2 (text{a} - text{b})(text{a} text{b})]We can apply this identity to (cos^4 x - sin^4 x), which can be rewritten as:
[cos^4 x - sin^4 x (cos^2 x)^2 - (sin^2 x)^2 (cos^2 x - sin^2 x)(cos^2 x sin^2 x).]Step 2: Simplification Using the Pythagorean Identity
From the Pythagorean identity, we know that:
[cos^2 x sin^2 x 1]Substituting this into our factored expression, we get:
[(cos^2 x - sin^2 x)(cos^2 x sin^2 x) (cos^2 x - sin^2 x) times 1 cos^2 x - sin^2 x.]Step 3: Final Simplification
Thus, we have:
[cos^4 x - sin^4 x cos^2 x - sin^2 x.]Conclusion
This concludes the proof that the left-hand side equals the right-hand side:
[cos^4 x - sin^4 x cos^2 x - sin^2 x.]Therefore, the identity is proven. The key steps in the proof involved recognizing the difference of squares and applying the Pythagorean identity.
Expanding the Proof
Consider another way to write the expression:
[cos^4 x - sin^4 x (cos^2 x)^2 - (sin^2 x)^2.]Using the difference of squares identity again:
[(cos^2 x)^2 - (sin^2 x)^2 (cos^2 x - sin^2 x)(cos^2 x sin^2 x).]Substituting (cos^2 x sin^2 x 1) into the expression, we get:
[(cos^2 x - sin^2 x)(1) cos^2 x - sin^2 x.]Hence, we have shown that:
[cos^4 x - sin^4 x cos^2 x - sin^2 x.]Remembering Essential Relationships
One must remember the following relationships:
(text{a}^2 - text{b}^2 (text{a} - text{b})(text{a} text{b}))[Difference of Squares formula] (cos^2 x sin^2 x 1)[Pythagorean Identity]Additionally, note that (cos^4 x (cos^2 x)^2) and (sin^4 x (sin^2 x)^2). Let (a cos^2 x) and (b sin^2 x). Then:
[(cos^2 x)^2 - (sin^2 x)^2 a^2 - b^2 (a - b)(a b) cos^2 x - sin^2 x (cos^2 x sin^2 x) cos^2 x - sin^2 x.]This reaffirms that:
[cos^4 x - sin^4 x cos^2 x - sin^2 x.]And therefore, we have provided a detailed proof that the given identity holds true.